Find $|A|$, $|B|$, $AB$, and $|AB|$. Then verify that $|A||B| = |AB|$.
$$A = \begin{bmatrix} 0 & 1 & 2 \\ 5 & 4 & 3 \\ 7 & 6 & 8 \end{bmatrix}, B = \begin{bmatrix} 5 & 1 & 5 \\ 1 & -1 & 0 \\ 0 & 3 & -5 \end{bmatrix}$$
(a) $|A|$
-15
(b) $|B|$
45
(c) $AB$
(d) $|AB|$
