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Miguel Andrade

Miguel A.

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Applied multivariate statistical analysis

Applied multivariate statistical…

Richard Arnold… 6th Edition
Achievement 1,073 solutions

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(a) Evaluate $T^2$, for testing $H_0: \mu^{\prime}=[7,11]$, using the data $$ \mathbf{X}=\left[\begin{array}{cc} 2 & 12 \\ 8 & 9 \\ 6 & 9 \\ 8 & 10 \end{array}\right] $$ (b) Specify the distribution of $T^2$ for the situation in (a). (c) Using (a) and (b), test $H_0$ at the $\alpha=.05$ level. What conclusion do you reach?

Applied multivariate statistical analysis

Using the data in Example 5.1, verify that $T^2$ remains unchanged if each observation $\mathbf{x}_j, j=1,2,3$; is replaced by $\mathbf{C} \mathbf{x}_j$, where $$ \mathbf{C}=\left[\begin{array}{rr} 1 & -1 \\ 1 & 1 \end{array}\right] $$ Note that the observations $$ \mathbf{C} \mathbf{x}_j=\left[\begin{array}{l} x_{j 1}-x_{j 2} \\ x_{j 1}+x_{j 2} \end{array}\right] $$ yield the data matrix $$ \left[\begin{array}{lll} (6-9) & (10-6) & (8-3) \\ (6+9) & (10+6) & (8+3) \end{array}\right] $$

Applied multivariate statistical analysis

A physical anthropologist performed a mineral analysis of nine ancient Peruvian hairs. The results for the chromium $\left(x_1\right)$ and strontium $\left(x_2\right)$ levels, in parts per million (ppm), were as follows: $$ \begin{array}{r|rrrrrrrrr} \hline x_1(\mathrm{Cr}) & .48 & 40.53 & 2.19 & .55 & .74 & .66 & .93 & .37 & .22 \\ \hline x_2(\mathrm{St}) & 12.57 & 73.68 & 11.13 & 20.03 & 20.29 & .78 & 4.64 & .43 & 1.08 \end{array} $$ It is known that low levels (less than or equal to $.100 \mathrm{ppm}$ ) of chromium suggest the presence of diabetes, while strontium is an indication of animal protein intake. (a) Construct and plot a $90 \%$ joint confidence ellipse for the population mean vector $\mu^{\prime}=\left[\mu_1, \mu_2\right]$, assuming that these nine Peruvian hairs represent a random sample from individuals belonging to a particular ancient Peruvian culture. (b) Obtain the individual simultaneous $90 \%$ confidence intervals for $\mu_1$ and $\mu_2$ by "projecting" the ellipse constructed in Part a on each coordinate axis. (Alternatively, we could use Result 5.3.) Does it appear as if this Peruvian culture has a mean strontium level of 10 ? That is, are any of the points $\left(\mu_1\right.$ arbitrary, 10$)$ in the confidence regions? Is $[.30,10]^{\prime}$ a plausible value for $\mu$ ? Discuss. (c) Do these data appear to be bivariate normal? Discuss their status with reference to $Q-Q$ plots and a scatter diagram. If the data are not bivariate normal, what implications does this have for the results in Parts a and b? (d) Repeat the analysis with the obvious "outlying" observation removed. Do the infer. ences change? Comment.

Applied multivariate statistical analysis

Harry Roberts, a nâturalist for the Alaska Fish and Game department, studies grizzly bears with the goal of maintaining a healthy population. Measurements on $n=61$ bears provided the following summary statistics (see also Exercise 8.23): $$ \begin{array}{l|cccccc} \text { Variable } & \begin{array}{c} \text { Weight } \\ (\mathrm{kg}) \end{array} & \begin{array}{c} \text { Body } \\ \text { length } \\ (\mathrm{cm}) \end{array} & \begin{array}{c} \text { Neck } \\ (\mathrm{cm}) \end{array} & \begin{array}{c} \text { Girth } \\ (\mathrm{cm}) \end{array} & \begin{array}{c} \text { Head } \\ \text { length } \\ (\mathrm{cm}) \end{array} & \begin{array}{c} \text { Head } \\ \text { width } \\ (\mathrm{cm}) \end{array} \\ \hline \begin{array}{l} \text { Sample } \\ \text { mean } \bar{x} \end{array} & 95.52 & 164.38 & 55.69 & 93.39 & 17.98 & 31.13 \end{array} $$ $\mathbf{S}=\left[\begin{array}{rrrrrr}3266.46 & 1343.97 & 731.54 & 1175.50 & 162.68 & 238.37 \\ 1343.97 & 721.91 & 324.25 & 537.35 & 80.17 & 117.73 \\ 731.54 & 324.25 & 179.28 & 281.17 & 39.15 & 56.80 \\ 1175.50 & 537.35 & 281.17 & 474.98 & 63.73 & 94.85 \\ 162.68 & 80.17 & 39.15 & 63.73 & 9.95 & 13.88 \\ 238.37 & 117.73 & 56.80 & 94.85 & 13.88 & 21.26\end{array}\right]$ (a) Obtain the large sample $95 \%$ simultaneous confidence intervals for the six population mean body measurements. (b) Obtain the large sample $95 \%$ simultaneous confidence ellipse for mean weight and mean girth. (c) Obtain the $95 \%$ Bonferroni confidence intervals for the six means in Part a. (d) Refer to Part b. Construct the $95 \%$ Bonferroni confidence rectangle for the mean weight and mean girth using $m=6$. Compare this rectangle with the confidence ellipse in Part b. (e) Obtain the $95 \%$ Bonferroni confidence interval for mean head width $\sim$ mean head length using $m=6+1 \approx 7$ to allow for this statement as well as statements about each individual mean.

Applied multivariate statistical analysis

Questions asked

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Khushbu Rani verified

Numerade educator

Prove that the equation \[ x^3 + 3y^3 + 9z^3 - 9xyz = 0 \] has no solutions other than the trivial solution \[ x = y = z = 0. \]

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Khushbu Rani verified

Numerade educator

puebe que la ecuación \[ x^3 + 3y^3 + 9z^3 - 9xyz = 0 \] no tiene solución aparte de la trivial \[ x = y = z = 0 \]

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Brian Beasley verified

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Prove that if \( n, k \) and \( m \) are natural numbers such that \( n = km \), then \((m!)^k | n!\).

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Penny Riley verified

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what is the value of gcd(a^2+b^2, a + b) if a and b are relatively prime?

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Brian Beasley verified

Numerade educator

## Problem If \( x, y \in \mathbb{Z} \) and \( n \in \mathbb{N} \), prove that \[ x - y \mid x^n - y^n. \]

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Khushbu Rani verified

Numerade educator

## Problema Demuestre que la fracción \[ \frac{21n + 4}{14n + 3} \] es irreducible para todo \( n \) entero positivo.

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Find all pairs \( (n, k) \) of natural numbers such that: \[ n! + 5n = k^2 - 13. \]

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Danielle Fairburn verified

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1. Prove using the Well-Ordering Principle that for \( n \in \mathbb{N} \) with \( n \geq 7 \), the following inequality holds: \[ \left( \frac{4}{3} \right)^n > n. \]

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Nick Johnson verified

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Find the number of binary sequences of length \( 2021 \) that do not have two consecutive zeros.

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Brian Beasley verified

Numerade educator

Prove that if \( p \) is a prime number: \[ 1^3 + 2^3 + 3^3 + \dots + (p-1)^3 \equiv 0 \pmod{p}. \]

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