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montserrat hunter

montserrat h.

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The estimated regression model is given by y hat =b_(0) b_(1)x=25675.5 5321^(**)x. What is the interpretation of b_(1) ? When mean score on teaching evaluation increases by 1, average annual salary increases by 25675.5 dollars. When mean score on teaching evaluation increases by 1 , average annual salary increases by 5321 dollars. When annual salary increases by a dollar, mean score on teaching evaluation increases by 5321. When annual salary increases by a dollar, mean score on teaching evaluation increases by 25675.5 .

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bill has a need to protect his mortgage with limited funds available. which might be the best product to recommend

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looks for hidden patterns and unknown relationships among the data a firm has accumulated. Multiple Choice Data parsing Tracking software Econometric analysis Data mining

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3 1 point Each value represents a different aqueous solution at 25°C. Classify each solution as an acid, base, or neutral. pH=3.03 POH= 3.16 pH= 13.15 [OH-]=5.0 × 10?? [H+]=1.0 x 10?? pH= 3.03 is a(n) Acid pH=13.15 is a(n) choose your answer... Neutral pOH= 3.16 is a(n) Base ?[OH-]= 5.0 x 10?? is a(n) [H+]= 1.0 x 10?? is a(n) Base ?

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Extra Problems for Studying For all problems, use g = 10.0 \frac{m}{s^2} for the gravitational acceleration constant. g=10.0 \frac{m}{s^2} M=56kg\newline\mu_k=0.70 Problem 1) Stark is moving his lawn; this can be imagined as a block of mass m with a force applied due to push at an angle to the horizontal. The lawnmower handle is at an angle of 30 degrees to the horizontal and has a mass of 56 kg. The grass is particularly dry this season and exerts friction on the lawn mower, physicists did some weird experiments with the grass and said the coefficient of kinetic friction of the grass is \mu_k=0.70. a) Draw a force diagram for the lawn mower. My attempts \vec{f}_n \vec{S}\rightarrow \vec{f}_{push} \vec{f}_g App b) Write the sum of forces, Fnetx & Fnety, for the lawnmower. App \quad F_{nety} = F_n - (mg + F_{push} \cdot sin(30^\circ)) \quad F_{nety} = 0 \text{ not lifting up/down} c) The lawnmower breakdown after mowing for 23 meters. How much work was done by friction during this time? App \quad W_f = F_f \cdot d \cdot cos \theta F_{normal} = mg - F_{push} \cdot sin(30^\circ) \quad \mu_k \cdot 56kg \cdot 10 \frac{m}{s^2} - F_{push} \cdot 0.5 d) Assume that the lawnmower moved at constant velocity, what is the work done by stark to push the lawnmower before breaking down? App \quad W_{stark} = -W_{Friction} W_{stark} =

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Generics may contain more than one different type of argument. O True O False

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Suppose a consumer can afford to buy 6 units of good 1 and 8 units of good 2 if she spends her entire income. The prices of the two goods are P1=6 and P2= 8 respectively. How much is the consumers income?

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Practical 2 Use matlab to compute the convolution $y(t) = x(t) * h(t)$ for the signals: Input: $x(t) = t^3 [u(t+4) - u(t-4)]$ Output: $h(t) = e^{-2t}cos(3t)u(t)$ Provide the Matlab code: < Insert your function program here. > Use the subplot function in Matlab to display $x(t)$ and $h(t)$ and the convolution result $h(t)$. < Paste matlab script here. > < Insert MATLAB figure here. > [5]

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Text: Need help figuring out the one in red boxes. Keeps saying the answer is wrong, but I can't seem to figure out how. Trial 1: Concentration of iodide solution (mM): 150.6 Concentration of thiosulfate solution (mM): 94.7 Concentration of hydrogen peroxide solution (mM): 220.5 Temperature of iodide solution (°C): 25.0 Volume of iodide solution I used (mL): 10.0 Volume of thiosulfate solution (S032-) used (mL): 1.0 Volume of DI water used (mL): 2.5 Volume of hydrogen peroxide solution (HO) used (mL): 7.5 Time (s): 28.0 Turned to a blue color: Observations Initial concentration of iodide in reaction (mM): 71.7 Initial concentration of thiosulfate in reaction (mM): 4.5 Initial concentration of hydrogen peroxide in reaction (mM): 78.75 Initial Rate (mM/s):

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Text: Question 3 (12 marks.) (MATH2011/2100/7100) A textiles company would like to know the thermal properties of a new material. The material is 1 cm thick and is primarily constructed of polyester with an overall thermal diffusivity of c^2 = 0.2 cm^2/s. As part of the testing procedure, the material is wrapped around a drum, placed in an environment at a temperature of 10°C, and the drum's temperature is regulated so that the temperature gradient on the outer surface of the material is 25°C/cm. (a) Give one reason why a 1-dimensional heat equation is appropriate here, and thus deduce a model of heat transfer through the material could be ∂T/∂t = 0.2∂^2T/∂x^2, T(x,0) = 10, T(0,t) = 10, T(1,t) = 35, where T is temperature (°C), x is depth into the material (cm), and t is time (seconds). (b) Write T(x, t) = Tsteady(x) + Ttransient(x, t) where Tsteady(x) is the steady state solution and Ttransient(x, t) is the transient. Show that the steady state solution is Tsteady(x) = 10 + 25x and T satisfies the following equations: 0.2∂^2Tsteady/∂x^2 = 0, Tsteady(0) = 10, Tsteady(1) = 35. (c) Use separation of variables, T(x, t) = F(x)G(t), to show that T(x, t) = Σ[50(1/n+1)sin(nπx)e^(-0.2(nπ)^2t)], where Σ denotes the sum over all non-negative integers n and m.

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