[10] Rewrite \int_0^{16} \int_0^{\sqrt{x}} \int_0^{16-x} dz \, dy \, dx in the order $dx \, dz \, dy$.
A) $\int_0^4 \int_0^{16-y^2} \int_{y^2}^{16-z} dx \, dz \, dy$
B) $\int_0^4 \int_0^{16-y} \int_{y^2}^{16-z} dx \, dz \, dy$
C) $\int_0^4 \int_0^{\sqrt{16-y}} \int_{y^2}^{16-z} dx \, dz \, dy$
D) $\int_0^4 \int_0^{16} \int_{y^2}^{16-z} dx \, dz \, dy$