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The Central Limit Theorem is crucial because it helps statisticians understand which aspect of sampling distributions

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We know that $y_1(x) = e^{-6x}$ is a solution to the differential equation $D^2y - 13Dy - 114y = 0$ for $x \in (-\infty, \infty)$. Use the method of reduction of order to find the second solution to $D^2y - 13Dy - 114y = 0$ for $x \in (-\infty, \infty)$. (a) After you reduce the second order equation by making the substitution $w = u'$, you get a first order equation of the form $w' = f(x, w) =$ Note: Make sure you use a lower case w, (and don't use w(t), it confuses the computer). (b) A second solution to $D^2y - 13Dy - 114y = 0$ for $x \in (-\infty, \infty)$ is $y_2(x) =$

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$h = \frac{1}{2}, h = \frac{1}{4}, h = \frac{1}{2}$ $T_o(\frac{1}{2}) = T_o(h) = \frac{h}{2} [f(x_o) + f(x_n)] + h \sum_{i=1}^{n-1} f(x_i)$ $= \frac{1}{2} \cdot \frac{1}{2} [\frac{2}{\frac{1}{2}} + \frac{2}{\frac{3}{2}}] + \frac{1}{2} \cdot \frac{2}{\frac{3}{2}} = \frac{1}{4} [6\frac{2}{3}] + \frac{1}{3} = \frac{3}{8} + \frac{1}{3} = \frac{17}{24} \approx 0.70833$ $T_o(\frac{1}{4}) = \frac{1}{2} (\frac{1}{4} + \frac{4}{7}) + \frac{1}{4} (\frac{4}{5} + \frac{5.7}{5.5} + \frac{5.6}{6.7})$ $= \frac{1}{8} (4 + \frac{4(2)}{210} + \frac{35}{210} + \frac{30}{210}) = \frac{1}{8} (4 + \frac{62}{210} + \frac{35}{210} + \frac{30}{210})$ $T_1 = \frac{4 \cdot T_o(\frac{1}{4}) - T_o(1)}{3}$ $= \frac{4 \cdot \frac{17}{24} - \frac{3}{8}}{3} = \frac{68 - 18}{24 \times 3} = \frac{50}{72} \approx 0.69444$ $f(x) = \frac{1}{x}$ $\frac{34 - 9}{36} = \frac{25}{36}$

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c. 3 molekul asam oksalat dihidrat, $ \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} $. Jawab: a. Tiap molekul air (lihat Gambar 3.2a) mengandung 2 atom H dan 1 atom $ \mathrm{O}\left(\mathrm{H}_{2} \mathrm{O}\right) $. Maka, dalam 3 molekul air terdapat: Atom $ H=3 \times 2=6 $ atom Atom $ O=3 \times 1=3 $ atom. b. Tiap molekul urea (lihat Gambar 3.2b) mengandung 1 atom $ \mathrm{C}, 1 $ atom $ \mathrm{O}, 2 $ atom N , dan 4 atom H (jadi rumus empirisnya $ \mathrm{CON}_{2} \mathrm{H}_{4} $ ). Maka, dalam 2 molekul urea terdapat: Atom $ C=2 \times 1=2 $ atom. Atom $ O=2 \times 1=2 $ atom. Atom $ N=2 \times 2=4 $ atom. Atom $ H=2 \times 4=8 $ atom. c. 3 molekul asam oksalat dihidrat $ \left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}\right) $ mengandung Atom $ \mathrm{H}=3 \times(2+4)=18 $ atom. Atom $ C=3 \times 2=6 $ atom. Atom $ O=3 \times(4+2)=18 $ atom. UiKepahaman 1. Tentukan jenis unsur dan jumlah atom masing-masing unsur dalam rumus kimia berikut: a. amonia, $ \mathrm{NH}_{3} $ b. glukosa, $ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} $ c. urea, $ \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2} $ d. asam cuka, $ \mathrm{CH}_{3} \mathrm{COOH} $ 2. Berapa atom oksigen yang terdapat dalam:

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Clifford makes a distinction between the content of beliefs (what one believes) and the origin of one’s belief (or how one comes to believe in something). Which of the two is the basic focus of his Clifford’s discussion, and why is the distinction relevant to his theme of the “ethics of belief”?

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What is the cause of the "goose bumps" when a person experiences cold, fear, and/or a touch? ? Activation of sebaceous glands ? Contraction of arrector pili muscles ? Stimulation of tactile (Meissner's) corpuscles

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A negative nitrogen balance results from a net loss of Group of answer choices monosaccharides. amino acids. genes. macronutrients.

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PREVIOUS ANSWER: ARCS & ANGLES IN CIRCLES Scavenger Hunt 62° E What is the measure of \stackrel\frown{RVU}? R S 65° 79° T V U Gina Wilson (All Things Algebra®, LLC), 2014-2022

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The elderly are susceptible to choking because: • a. They are usually confused • b. They have a decreased cough reflex • с. Their esophagus is smaller than a younger person • d. Their salivary glands produce less saliva, making it more difficult to swallow.

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Find the limit. (If an answer does not exist, enter DNE.) lim_(x->56)(sqrt(x+8)-8)/(x-56) Find the limit. (If an answer does not exist, enter DNE.) Vx+8-8 lim x-56 X-56

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