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nerea iborra

nerea i.

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Write the following expression as a single definite integral of the form $\int_a^b f(x) dx$. $\int_{-4}^2 f(x) dx + \int_2^5 f(x) dx - \int_{-4}^{-1} f(x) dx$

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Certain cells within the pancreas function in the synthesis and secretion of the hormone insulin, which is a protein. Based on this function, what organelle(s) do you predict these cells would contain large numbers of?

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Should privacy or Fourth Amendment laws be changed due to the increased level of technology that exists today? Should people accept that their privacy is reduced due to their use of technology, or should there be more restrictions on how the government can use technology to monitor citizens? Is our quality of life improved or harmed by the government's increasing ability to monitor our behavior due to the technology used on a daily basis? Explain.

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Q1. Build an ego network centered around yourself, including 5 to 10 significant individuals from your circles, such as family, friends, and business contacts. Draw connections between them as applicable. Calculate your clustering coefficient to gauge the cohesion of your network. Comment on how this interconnectedness influences your life.

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Show that the CBC MAC we studied is not UF-CMA secure if the domain contains messages of arbitrary length (but multiple of n bits), where n is the underlying block cipher’s block length. PROOF Given: - Encryption Scheme: CBC MAC - Message Space (MsgSp): Messages of arbitrary length (multiple of n bits) - Key Space (KeySp): Not specified Proof Attack: Consider an UF-CMA adversary who submits the following LR query: (M0, M1) and gets Tag. The adversary then applies the following algorithm: Submit a new message M' = M0||M1||M2, where M2 is an arbitrary block. Justification: The adversary can append an arbitrary block to the given messages M0 and M1 without affecting the validity of the tag. This allows the adversary to forge new valid tags for messages not previously queried. Advantage: AdvUF-CMA (A) = 1, as the adversary can always forge a valid tag with a new message. Resources: The resources required for this attack are reasonable; t: time to compute the tag, q: 1, µ: 2n, so reasonable resources. EXAMPLE: ECB IS NOT IND-CPA Given: - MsgSp = {0,1}^l * N = bitstring of length some multiple of l-sized blocks - KeySp = {0,1}^k = bitstring of length k - E: EK(Mi) = Ci where M = M1||M2||...||MN and C = C1||C2||...||CN - D: EK-1(Ci) = Mi where M = M1||M2||...||MN and C = C1||C2||...||CN - If Ma = Mb then Ca = Cb Proof Attack: Consider an IND-CPA adversary who submits the following LR query: (02n, 0n||1n) and gets C1||C2. The adversary then applies the following algorithm: If C1 = C2 then: Return left Else: Return right Justification: If 2 message blocks are the same then their ciphertexts are the same. Here we put in a left message with 2 identical blocks, which will result in 2 identical ciphertext blocks, and a right message with 2 completely different blocks, which will result in 2 different ciphertext blocks. An adversary knowing this behavior can check if the 2 ciphertext blocks are identical or not and easily determine if it is the left or right query. Advantage: AdvECB (A) = 1 Resources: t: time to compare n bits, q: 1, µ: 4n, so reasonable resources.

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has been shown to be effective intervention for post-traumatic stress disorder, chronic back pain, and chronic fatigue syndrome.

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Refer to the vectors below. b = [4, 2, 1] c = [1, -2, 1] d = [-1, -1, -4] Compute the indicated vector. 2b - 2c + d =

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Using the following table of transform pairs and properties, determine the z-transform of the sequence: $x[n] = \begin{cases} n, & 0 \le n \le N-1 \\ N, & n \ge N \end{cases}$ Table of transform pairs: \begin{tabular}{|c|c|c|} \hline Sequence & Transform & ROC \\ \hline $\mu[n]$ & $\frac{1}{1 - z^{-1}}$ & $|z| > 1$ \\ \hline $n a^n \mu[n]$ & $\frac{az^{-1}}{(1 - az^{-1})^2}$ & $|z| > |a|$ \\ \hline \end{tabular}

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5. How does muscle contraction starts? 6. What is the sliding filament model? 7. What valves close on the Lub sound? Dub sound? And due to what? 8. This system ensures heart muscle contraction allowing the heart to beat as a coordinated unit. 9. Where does it starts?

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3. A 10 cm long cantilever beam is subjected to a concentrated load of 10N at a distance of 1cm from its free end, as shown in Fig.3. The cross section of the beam is rectangular with height=2 cm and width=4cm. (a) Indicate the location and determine the value of the maximum tensile stress in the beam. If the beam is to be made of aluminum with a yielding stress of 290MPa, (b) determine whether the beam can withstand the load of 10N without yielding.

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