Consider the error formulas.
$|E| \leq \frac{(b-a)^3}{12n^2} \text{max } |f''(x)|, \ a \leq x \leq b \text{ Trapezoidal Rule}$
$|E| \leq \frac{(b-a)^5}{180n^4} \text{max } |f^{(4)}(x)|, \ a \leq x \leq b \text{ Simpson's Rule}$
Use these to estimate the errors in approximating the integral, with $n = 4$, using the Trapezoidal Rule and Simpson's Rule.
$\int_2^6 \frac{1}{(x-1)^2} dx$
(a) Trapezoidal Rule
120
(b) Simpson's Rule
0.0833
