Question 1 options:A 20.00 L container contains a gas at 50.0 oC and 1.000 atm. What would be the pressureat 200.0 oC ?This is a change in conditions problem, we need to define the variables:V1 = 20.0 L T1 = 323.15 K P1 = __1__ atmV2 = __2__ L T2 = __3__ K P2 = ?The problem doesn't mention the moles, n, thus the amount of moles was not changedand n1 = __4__ P2 V2 P1 V1 P2 P1 = The equation simplifies to = n2 T2 n1 T1 T2 T1 P1 __5__ solving for P2 = -------------- __6__ __7__ atm __8__ K putting in the numbers P2 = -------- = __9__ atm __10__ KA. n2 B. 20.0 C. 473.15 D. 323.15 E. 1.000 F. P1 G. P2 H. V1 I. V2 J. n1 K. T1 L. T2 M. 1.464 N. 0.08205 L atm/mol K O. 0.7543 P. 0.3270 Q. 12.6 R. 0.333 S. 3.000 T. 0.667 U. 99.38 V. 298.15 W. 2.000 X. 6.000 Y. 4.000 Z. 1.333 AA. 0.3270 BB. 7.329 CC. 22.414 DD. 32.00 EE. 10.46 FF. 1.428