Equilateral triangle with the length of each side a = 27 cm, see the picture below. The masses are m₁ = 8.5 kg (located at the origin), m₂ = 8 kg (located along the positive x-direction), and m₃ = 12.5 kg. Find the position of the center of mass of the system.
The x-component of the CoM position, XCOM =
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The y-component of the CoM position, YCOM
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The potential energy of the system, PEG =
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g X
Using the CoM position find the gravitational potential energy of the entire system relative to the y = 0 level. Note that PEG = mtot S YCOM, where mtot is the total mass of the system and YCOM is the y-component of the CoM position.
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