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patricia stevens

patricia s.

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12.53 Consider a point in a structural member that is subjected to plane stress. Normal and shear stresses acting on horizontal and vertical planes at the point are shown. 50 ksi 32 ksi (a) Determine the principal stresses and the maximum in-plane shear stress acting at the point. (b) Show these stresses on an appropriate sketch (e.g., see Fig. 12.15 or Fig. 12.16) 10 ksi (c) Compute the absolute maximum shear stress at the point. Instructors: Problems 12.53-12.56 should be assigned as a set. Fig. P12.53

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An investment bank agrees to underwrite a $100 million, 15-year, 10 percent semiannual bond issue for a company on a firm commitment basis. The investment bank pays the company on Monday and plans to begin a public sale on Tuesday. If interest rates rise 0.5 percent, or fifty basis points, overnight, what will be the impact on the profits of the investment bank? $4,258.365; loss $4,258,365: gain $3,735,975; loss $3,735,975: gain

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Do you think lipase is an enzyme that is found in the stomach

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You bought a new car for $22,500 in 2005, and the value of the car depreciates by $900 each year. Find a formula for , the value of the car, in terms of , the number of years since 2005.

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a market portfolio is a well-diversified portfolio constructed to have a beta of 1 on one of the factors and a beta of 0 on any factor

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Microevolution (changes in allele frequencies) can lead to macroevolution, but one force of evolution that is important in microevolution cannot lead to macroevolution. Which force of evolution prevents the formation of a new species? Group of answer choices gene flow mutation genetic drift natural selection

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folecular mass of an unknown acid. 1. Unknown number 2. Molarity of sodium hydroxide solution 0.5 g Titrations 3. Mass of flask + unk. 4. Mass of flask 5. Mass of unknown 6. Final buret reading 8. Initial buret reading 9. Volume of NaOH soln. 10. Moles of unknown acid (assume monoprotic) 11. Molecular mass of acid 12. Average molecular mass of acid 13. Deviation of each mol . mass from average flask \( x^{2} \) flask \ \( x^{1} \) \( \qquad \) \( \qquad \) \( \qquad \) \( \qquad \) \( \qquad \) \( \qquad \) \( \qquad \) \( \qquad \) 129.689 \( \qquad \) 129.189 \( \qquad \) 0.5 mL \( \qquad \) 6.7 mL \( \qquad \) O(2) \( \qquad \) 0.5 mL \( \qquad \) 1.00005 \( \qquad \) \( 10180 \mathrm{~g} / \mathrm{mol} \) \( \qquad \) \( \qquad \) \( \qquad \) \( 10180 \mathrm{~g} / \mathrm{mol} \) \( \qquad \) \( \qquad \) \( \qquad \) 14. Average deviation of molecular mass \( \qquad \) 15. Suggest experimental modifications you could make if the acid to be titrated has low solubility in water. - adding neat to onange temperatue - Different nays of stirring the mixtore - adding more water 16. Some of the Learning Objectives of this experiment are listed on the first page of this experiment. Did you achieve the Learning Objectives? Explain your answer. Yes. The learned how the PH belance of a mixture 02015 Cengage Leaming. All Rights Reserved May not be seanned, copied or duplicated, or posted to a publicly accessible websile, in whole or in part.

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4. Greek philosophers who believed reasoning would uncover ideals or core ideas were focused on which aspect of psychology?

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Calculate the current and voltage Through the capacitor and resistors. The values are 10V, 1 kOhm, 330 mF

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divorce is a data frame with 77 observations on the following 7 variables. year: the year from 1920-1996 divorce: divorce per 1000 women aged 15 or more unemployed unemployment rate femlab: percent female participation in labor force aged 16+ marriage: marriages per 1000 unmarried women aged 16+ birth: births per 1000 women aged 15-44 military: military personnel per 1000 population # Load in the data divorce = read.csv("divusa.txt", sep=" ") summary(divorce) head(divorce) A data.frame: 6 imes 7 year divorce unemployed femlab marriage birth military 2a)Using the divorce data, with divorce as the response and all other variables as predictors, select the "best" regression model, where "best" is defined using AIC. Save your final model as lm_divorce.** #lm_divorce = NA # your code here year divorce unemployed femlab Min. :1920 Min. :6.10 Min. : 1.200 Min. 22.70 1st Qu.:1939 1st 0u.: 8.70 1st Qu.: 4.200 1st Qu.:27.47 Median :1958 Median :10.60 Median : 5.600 Median :37.10 Mean :1958 Mean :13.27 Mean : 7.173 Mean :38.58 3rd Qu.:1977 3rd Qu.:20.30 3rd Qu.: 7.500 3rd Qu.:47.80 Max. :1996 Max. 22.80 Max. 24.900 Max. :59.30 marriage birth military Min. 49.70 Min. 65.30 Min. 1.940 1st Qu.: 61.90 1st Qu.: 68.90 1st Qu.: 3.469 Median : 74.10 Median : 85.90 Median : 9.102 Mean 72.97 Mean 88.89 Mean 12.365 3rd Qu.: 80.00 3rd Qu.:107.30 3rd Qu.:14.266 Max. :118.10 Max. :122.90 Max. 86.641 A data.frame: 6 7 year divorce unemployed femlab marriage birth military <int> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> 1 1920 8.0 5.2 22.70 92.0 117.9 3.2247 2 1921 7.2 11.7 22.79 83.0 119.8 3.5614 3 1922 6.6 6.7 22.88 79.7 111.2 2.4553 4 1923 7.1 2.4 22.97 85.2 110.5 2.2065 5 1924 7.2 5.0 23.06 80.3 110.9 2.2889 6 1925 7.2 3.2 23.15 79.2 106.6 2.1735

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