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patrick verdugo

patrick v.

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8. How would the above analysis change if you knew that she would collect $2,000 in social security benefits each month? Traditional IRA

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A. 0.500 mol sample of hydrogen is at 300 K . Find the number of molecules having speed between \( 400 \mathrm{~m} \mathrm{~s}^{-1} \) and \( 401 \mathrm{~m} \mathrm{~s}^{-1} \) the mass of hydrogen is \( 1.67 \times 10^{-27} \mathrm{~kg} \) and the Boltzmann constant \( k_{B}= \) \( 1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K} \). And \( \left(N_{A}=6.02 \times 10^{23} \mathrm{~mol}^{-1}\right) \operatorname{Hint}\left(n=\frac{N}{N_{A}}\right) \)

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Ch 12 4. Assume you purchased a corporate bond at its current market price of $1900 on January 1, 2019. It pays 6 percent interest annually on December 31 and will mature on December 31, 2025, at which time the corporation will pay you the face value of $2,000. a. Determine the current yield on your bond investment at the time of purchase. Current yield = Interest income ÷ Current market value Current yield = $60 divided by $1900 = 3.16 percent

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A 2.0-kg cart attached to a spring undergoes simple harmonic motion so that its displacement is described by x = (0.20m)sin[(2Ï€/2.0s)t]. What is the total energy of the system? Choose the correct energy bar charts. (T is the period of oscillation.)

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A. mg-N=m(r)/(r) B. mg+N=m(v^(2))/(r) C. mg-N=-m(v^(2))/(r) D. mg+N=-m(v^(2))/(r) 12. Consider case 2. What is the centripetal force that keep the rider in circular motion? A. Gravitational force B. Normal force (upward) C. Normal force (downward) D. The net force of gravitational force and normal force (upward) E. The net force of gravitational force and normal force (downward) 13. Choose down as positive. Select the correct equation of Newton's second law for case 2. Hint: Draw free-body diagram, draw vector centripetal force, and watch for signs of forces and centripetal acceleration. A. mg-N=m(v^(2))/(r) B. mg+N=m(v^(2))/(r) C. mg-N=-m(v^(2))/(r) D. mg+N=-m(v^(2))/(r) 14. Consider case 3. What is the centripetal force that keeps the rider in circular motion? A. Gravitational force B. Normal force (upward) C. Normal force (downward) D. The net force of gravitational force and normal force (upward) E. The net force of gravitational force and normal force (downward) 15. Choose down as positive. Select the correct equation of Newton's second law for case 3. Hint: Draw free-body diagram, draw vector centripetal force, and watch for signs of forces and centripetal acceleration. A. mg-N=m(v^(2))/(r) B. mg+N=m(v^(2))/(r) C. mg-N=-m(v^(2))/(r) D. mg+N=-m(v^(2))/(r) A.mg-N B.mg+N= C.mg-N=-m D.mg+N=-m 12.Consider case 2.What is the centripetal force that keeps the rider in circular motion? A.Gravitational force B.Normal force(upward) C.Normal force(downward) D. The net force of gravitational force and normal force (upward) E.The net force of gravitational force and normal force(downward) 13. Choose down as positive. Select the correct equation of Newton's second law for case 2. Hint: Draw free-body diagram, draw vector centripetal force, and watch for signs of forces and centripetal acceleration. C.mg-N=-m D.mg+N=-m 14.Consider case 3.What is the centripetal force that keeps the rider in circular motion? A.Gravitational force B.Normal force(upward) C.Normal force(downward) D.The net force of gravitational force and normal force (upward) E. The net force of gravitational force and normal force (downward) 15.Choose down as positive.Select the correct equation of Newton's second law for case 3 Hint: Draw free-body diagram, draw vector centripetal force, and watch for signs of forces and centripetal acceleration. A.mg-N=m B.mg+N=m D2 C.mg-N=-m D.mg+N=-m

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What is the concentration in molarity of a solution which is 3.07 %m/v xylene (MM = 106.2 g/mol ) in toluene (MM = 92.30 g/mol)?

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If $M$ is an $R$-module and $A$, $B$, $C$ are submodules of $M$ such that $A \le B$, $A + C = B + C$, $A \cap C = B \cap C$. Prove that $A = B$.

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The message m(t) is applied to a frequency modulator with sensitivity 7.8 Hz/V and unmodulated carrier frequency of 2000Hz. m(t) = 2.3t[u(t) - u(t - 2.5)] Find the peak frequency deviation defined as the maximum deviation from the unmodulated carrier frequency. The answer should be a number rounded to 5 decimal digits (the minus sign is accepted while other symbols like % are not)

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9. A recent finding shows that the probability of giving birth to a girl is 0.57. Correct your answers to 4 decimal places. (a) A couple plan to have 2 children. Find the probability that both of the 2 children are boys? (2 marks) (b) Another couple plan to have 3 children. Find the probability that at least one of them is a girl? (3 marks)

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The codon GUC corresponds to the anticodon: O CAG O GUC O CAC O GUA

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