Questions asked
An individual has purchased \( \$ 10,000 \) worth of \( X Y Z \) Company's stock at \( \$ 50 \) per share, and later sells the stock at \( \$ 60 \) per share. How much did the individual make from the transaction? \$10,000 \$15,000 \$1,000 \$5,000
The mayor of a town believes that under 36% of the residents favor construction of an adjoining bridge. Is there sufficient evidence at the 0.05 level to support the mayor's claim? After information is gathered from 380 voters and a hypothesis test is completed, the mayor decides to reject the null hypothesis at the 0.05 level. What is the conclusion regarding the mayor's claim?
A hospital director is told that 44% of the treated patients are uninsured. The director wants to test the claim that the percentage of uninsured patients is more than the expected percentage. A sample of 330 patients found that 165 were uninsured. At the 0.01 level, is there enough evidence to support the director's claim? Step 3 of 7 : Specify if the test is one-tailed or two-tailed.
A hospital director is told that 44% of the treated patients are uninsured. The director wants to test the claim that the percentage of uninsured patients is more than the expected percentage. A sample of 330 patients found that 165 were uninsured. At the 0.01 level, is there enough evidence to support the director's claim? Step 1 of 7 : State the null and alternative hypotheses.
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1200 voters in the town and found that 76% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is above 73% . Testing at the 0.10 level, is there enough evidence to support the strategist's claim? Step 2 of 7 : Find the value of the test statistic. Round your answer to two decimal places.
A hospital director is told that 79% of the emergency room visitors are insured. The director wants to test the claim that the percentage of insured patients is not the expected percentage. A sample of 340 patients found that 255 were insured. At the 0.05 level, is there enough evidence to support the director's claim? Step 3 of 7 : Specify if the test is one-tailed or two-tailed.
A hospital director is told that 79% of the emergency room visitors are insured. The director wants to test the claim that the percentage of insured patients is not the expected percentage. A sample of 340 patients found that 255 were insured. At the 0.05 level, is there enough evidence to support the director's claim? Step 1 of 7 : State the null and alternative hypotheses.
Officials in charge of televising an international chess competition in South America want to determine if the average time per move for the top players has remained at 6 minutes over the last two years. Video tapes of matches which have been played over the two-year period are reviewed and a random sample of 50 moves are timed. The sample mean is 5.5 minutes. Assume the population standard deviation is 2.8 minutes. Using the confidence interval approach, test the hypothesis that the average time per move is different from 6 minutes at a 0.05 significance level. Step 2 of \( \mathbf{2} \) : Draw a conclusion and interpret the decision. Answer Tables Keypad Keyboard Shortcuts previous step answer Because the hypothesized value falls in the confidence interval, we fail to reject the null hypothesis. There is not sufficient evidence at the 0.05 significance level that the average time per move is different from 6 minutes. Because the hypothesized value does not fall in the confidence interval, we reject the null hypothesis. There is sufficient evidence at the 0.05 significance level that the average time per move is different from 6 minutes. Because the hypothesized value does not fall in the interval, we fail to reject the null hypothesis. There is not sufficient evidence at the 0.05 significance level that the average time per move is different from 6 minutes. Because the hypothesized value falls in the interval, we reject the null hypothesis. There is sufficient evidence at the 0.05 significance level that the average time per move is different from 6 minutes.
A group of local businessmen is thinking about developing land into a shopping mall. To evaluate the desirability of the location, they count the number of shoppers who visit the neighboring shopping center each day. A random sample of 53 days reveals a daily average of 88 shoppers with a standard deviation of 42 shoppers. The businessmen will develop the land if the average number of shoppers per day is more than 80 . Based on the sample data, should the businessmen develop the land? Perform a hypothesis test and use a significance level of \( \alpha=0.05 \). Assume the population of the number of daily shoppers is approximately normally distributed. Step 3 of \( \mathbf{3} \) : Draw a conclusion and interpret the decision. Answer Tables Keypad Keyboard Shortcuts We reject the null hypothesis and conclude that there is sufficient evidence at a 0.05 level of significance to support the claim that the average number of shoppers per day is large enough to develop the land. We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 0.05 level of significance to support the claim that the average number of shoppers per day is large enough to develop the land. We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.05 level of significance to support the claim that the average number of shoppers per day is large enough to develop the land. We reject the null hypothesis and conclude that there is insufficient evidence at a 0.05 level of significance to support the claim that the average number of shoppers per day is large enough to develop the land.
Hurricane Andrew swept through southern Florida causing billions of dollars of damage. Because of the severity of the storm and the type of residential construction used in this semitropical area, there was some concern that the average claim size would be greater than the historical average hurricane claim of \( \$ 24,500 \). Several insurance companies collaborated in a data gathering experiment. They randomly selected 24 homes and sent adjusters to settle the claims. In the sample of 24 homes, the average claim was \( \$ 27,000 \) with a population standard deviation of \( \$ 5200 \). Is there sufficient evidence at a 0.05 significance level to support the claim that the home damage is greater than the historical average? Assume the population of insurance claims is approximately normally distributed. Step 3 of 3 : Draw a conclusion and interpret the decision. Answer Tables Keypad Keyboard Shortcuts We reject the null hypothesis and conclude that there is insufficient evidence at a 0.05 level of significance to support the claim that the average home damage is greater than the historical average. We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.05 level of significance to support the claim that the average home damage is greater than the historical average. We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 0.05 level of significance to support the claim that the average home damage is greater than the historical average. We reject the null hypothesis and conclude that there is sufficient evidence at a 0.05 level of significance to support the claim that the average home damage is greater than the historical average.
