EMT 1220 Experiment #9 Automatic Control System - Question No. 7, Homework Solution #9a Motor- Single Phase AC, Capacitor Start Question No. 7 Input 2 T Ples ↑ Tape Flag A Note (A+B)/2=C where, A Differential 1 IF A=0.8 TURNS Prof. Razukas Spider Number of turns of Gear A B Number of turns of Gear B > C Number of turns of Output Shaft C 72 T MECHANIC BICOUNTFO B B = ZERO [HELD BY MOTOR 96 T 0 Worm and Wheel 60 Tooth Wheel Cam 60 T 30 T Limit Switch The Disturbance caused by Gear A turning 0.8 turns, resulted in Shaft C turning 0.4 turns. The Mechanical Counter, because of the speed multiplier, will read (2 X C) = (2 X 0.4) = 0.8 Turns. This is the same as the number of turns of A, which was the Disturbance. Output Shaft, C Speed Multiplier In order to counteract the Disturbance caused by Gear A, the input handle is now kept from moving such that A does not turn [A=0], and Gear B must now turn 0.8 turns in the opposite direction of gear A. If Gear B moves 0.8 Turns, calculate the number of turns of the Motor