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rebecca warren

rebecca w.

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A first-order reaction has rate constants of 4.7 10-2 s-1 and 8.0 10-2 s-1 at 0°C and 20.°C, respectively. What is the value of the activation energy? kJ/mol

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The medial surface of the left lung has a cavity that accommodates the contents of the mediastinum. It is called the _____. ? cardiac notch ? sternal indentation ? paraphrenic indentation ? medial notch

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hat \(f\) and \(g\) are inverse functions algebraically and graphically. \(f(x) = 6x + 1\), \(g(x) = \frac{x - 1}{6}\) (a) algebraically \(f(g(x)) = f(\boxed{\qquad}) = 6(\boxed{\qquad}) + 1 = x \(g(f(x)) = g(\boxed{\qquad}) = \frac{\boxed{\qquad} - 1}{6} = x (b) graphically

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Find the size of angle A in the triangle below given the lengths of b and a are b=7.3 cm and a=1.8 cm and angle B = 55°. Give your answer in degrees to one decimal place.

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In what computer context would you typically use the Paramiko library in Python? ? To automate web scraping tasks. ? To create graphical user interfaces (GUIs). ? To perform data analysis and visualization. ? To implement secure SSH communication. ? To generate secure cryptographic keys.

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Consider two charges q_(1)=4.15nC at x_(1)=0cm and q_(2)=2.61nC at x_(2)=30.5cm. A point A is a distance d=12.9cm to the right of q_(2). Point B is the same distance d=12.9cm to the right of q_(1). a) Find the electric field vector vec(E)_(1) due to q_(1) at A: vec(E)_(1)=,hat(i) b) Find the electric field vector vec(E)_(2) due to q_(2) at A: vec(E)_(2)=,hat(i) c) Find the electric field vector vec(E)_(A) due to both charges at A: vec(E)_(A)=,hat(i) d) Find the electric field vector vec(E)_(1B) due to q_(1) at B : vec(E)_(1B)=,hat(i) e) Find the electric field vector vec(E)_(2B) due to q_(2) at B : vec(E)_(2B)=,hat(i) F) Find the electric field vector vec(E)_(B) due to both charges at B: vec(E)_(B)=,hat(i) g) At what distance to the right of q_(1) would the electric field due to both charges be equal to zero? x= We replace q_(1) by an equal negative charge q_(1)=-4.15nC h) Find the new electric field vector vec(E)_(A) due to both charges at A: vec(E)_(A)=,hat(i) i) Find the new electric field vector vec(E)_(B) due to both charges at B : vec(E)_(B)=,hat(i) Consider two charges q1 = 4.15 nC at = 0 cm and q2 = 2.61 nC at 2 = 30.5 cm. A point A is a distance d = 12.9 cm to the right of q2. Point B is the same distance d = 12.9 cm to the right of q1. a) Find the electric field vector E due to q1 at A: E1 b) Find the electric field vector E2 due to q2 at A: E2 c) Find the electric field vector E4 due to both charges at A: EA= d) Find the electric field vector E1B due to q1 at B: EB e) Find the electric field vector E2B due to q2 at B: E2B F) Find the electric field vector EB due to both charges at B: EB (*6 g) At what distance to the right of q1 would the electric field due to both charges be equal to zero? We replace q1 by an equal negative charge q1 = -4.15 nC h) Find the new electric field vector E4 due to both charges at A: EA i) Find the new electric field vector EB due to both charges at B: EB=

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(2) What is the difference between MIS efficiency and MIS effectiveness? Support your answer by providing specific examples to address each of these two concepts.

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5. A long slot is cut from a steel bar as shown, if w = 4 in., t = 0.75 in., r = 0.7 in., $L_1$ = 1.5 ft., L = 8 ft., P = 24 kip and E = 30 \times 10^6 psi, find (a) the maximum stress in the rod and (b) the total elongation of the rod. Assume the stress-concentration factor for a round hole is applicable. When determining the elongation, assume the stress concentrations can be neglected and the slot extends the entire length L.

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Bonus (20 Points) A complicated multi-stage amplifier circuit has been reduced to the following equivalent two-port network, where the left side is the input side and the right side is the output side: where: $ \begin{bmatrix} I_1 \\ I_2 \end{bmatrix} = \begin{bmatrix} -70 \cdot 10^{-6} & 0 \\ 0.3 & .01 \end{bmatrix} \begin{bmatrix} V_1 \\ V_2 \end{bmatrix} $ Assuming that the output side is left open (no load), find: (a) The voltage gain of the amplifier? (5 points) $\circ$ gain = _____ (b) The input resistance of the amplifier (5 points) $\circ$ $R_{in}$ = _____ If the amplifier is now terminated with a load resistance of 500$\Omega$, find: (c) The voltage gain of the amplifier? (5 points) $\circ$ gain = _____ (d) The input resistance of the amplifier (5 points) $\circ$ $R_{in}$ = _____

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Section B Please specify a unique true/false or yes/no answer for each question. There are no negative marks for wrongly answered questions. 1.The identification of the fluid contacts is necessary to determine volumetrically hydrocarbon reserves a.True b.False 2.P50 lies halfway between P10 and P90 a.True b.False 3.P10 is lower than P90 a.True b.False 4.Material balance equation can be used to predict future production a.True b.False 5.Increasing the pressure of an undersaturated oil causes the increase of its vaue a.True b.False

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