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0.25/1 points | Previous Answers SerPSE10 25.3.OP.011.MI.
Consider the circuit shown in the figure below, where $C_1 = 8.00 \,\mu F$, $C_2 = 8.00 \,\mu F$, and $\Delta V = 18.0 \,\text{V}$. Capacitor $C_1$ is first
charged by closing switch $S_1$. Switch $S_1$ is then opened, and the charged capacitor is connected to the uncharged capacitor
by closing $S_2$.
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$\Delta V$
$S_1$
$C_1$
$S_2$
$C_2$
(a) Calculate the initial charge (in $\mu C$) acquired by $C_1$. (Round your answer to at least one decimal place.)
144 $\mu C$
(b) Calculate the final charge (in $\mu C$) on each capacitor. (Round your answers to at least the nearest integer.)
$Q_1 =$
$Q_2 =$
What is the equivalent capacitance of the two capacitors when switch $S_2$ is closed? $\mu C$
Remember that switch $S_1$ is already open when switch $S_2$ is closed, so no additional charge can be transferred
from the battery. $\mu C$
(c) What If? After a very long time, switch $S_1$ is also closed. By what amount does the charge on the second capacitor
change after $S_1$ has been closed for a very long time? (Give your answer in $\mu C$.)
$\mu C$
