Let the random variable X have the following pdf: $f(x) = 3(1 - x)^2$ where $0 < x < 1$. Suppose $Y = (2 - 2X)^3$. Find $g(y)$, the pdf of Y. Also, give the support of $g(y)$.
g(y) = 1/6, support is $0 < y < 6$
None of these answers are correct.
g(y) = 1/8, support is $0 < y < 8$
g(y) = 1/4, support is $0 < y < 4$
g(y) = 3/4, support is $0 < y < 1$