Given the following vector fields below, only one of them is conservative. The one that is conservative, find its potential function. Once you find the potential function, suppose we can apply a condition that f(1,0)=5. Solve for the constant and then evaluate f(2,3) to 2 decimal places.
F(x,y) = 5y^2 (3yi - xj)
F(x,y) = e^x (cos(y)i + sin(y)j)
F(x,y) = x/(x^2+y^2)i + y/(x^2+y^2)j
Remember, only one of these vector fields is conservative. Once you know which one is the right vector field, then determine its potential function f(x,y). Apply f(1,0)=5 to solve for the constant, then determine f(2,3) to 2 decimal places.