Calculate ?G of the reaction PCl5(g) ? PCl3(g) + Cl2(g) at 200 °C when the
partial pressures are: 0.40 atm for Cl2(g), 0.27 atm for PCl3(g),
and 0.0029 atm for PCl5(g). and
$\Delta H^0_f$ = {0.0 kj/mol for Cl2(g),
-306
kj/mol for PCl3(g), -399 kj/mol for PCl5(g)}.
$S^0$ = {0.223 kj/K for Cl2(g),
kj/K for PCl3(g),
0.312
0.364 kj/K for PCl5(g)}.