The point P(9, 5) lies on the curve
y = \sqrt{x} + 2. If Q is the point
(x, \sqrt{x} + 2), find the slope of the secant line
PQ for the following values of x.
If x = 9.1, the slope of PQ is:
.1662
and if x = 9.01, the slope of PQ is:
.1665
and if x = 8.9, the slope of PQ is:
and if x = 8.99, the slope of PQ is:
.1665
Based on the above results, guess the slope of the tangent
line to the curve at P(9, 5).