Values:
q₁ = -3.0 μC
q₂ = +2.0 μC
q₃ = +1.0 μC
Calculate the magnitude and direction of the electric force acting on charge q₂ due to the other charges.
12. The three point charges shown in the figure have the following values: q₁ = -3.0 C, q₂ = +2.0 C, q₃ = +1.0 C. Calculate the magnitude and direction of the electric force acting on charge q due to the other charges.
O (0 m, 0 m) +16 m, 0 m)
25 m
+1.0 x 10^-6
9.9 x 10^9 -3.0 x 10^-6 F = Ke(2 x 10^-6) / (25)^2 = 9.6 x 10^-6 x 9 Tan(6) = 12 = 3.87
F₂ = +2.0 x 16
F = 9.9 F = Ke(15)^2 / (25)^2
F = 9.9 x 10^9 x (15)^2 / (25)^2
F = 4.41 x 10^-6 cos(3.87) + 4.44 x 10^-6 sin(30.87)
F = (3.55 x 10^-6) + (2 x 15)
F = 4.436 x 10^-19
Recheck your initial calculation for F₃:
F₃ = √(F₁x)^2 + (F₂y)^2
F₃ = √(3.6 x 10^-6)^2 + (7.05 x 10^-6)^2
F₃ = 11.5 / cm
