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robin kim

robin k.

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Consider the chemical reaction that takes place between solid magnesium and oxygen gas. Write a balanced chemical equation based on the following description: solid magnesium metal reacts with oxygen gas to produce solid magnesium oxide. Mg (s) + O ₂ (g) → ⁴⁻ ³⁻ ²⁻ ⁻ ⁺ ²⁺ ³⁺ ⁴⁺ 1 2 3 4 5 6 7 8 9 0 ₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉ ₀ + ( ) → ⇌ (s) (l) (g) (aq) H Mg O NR

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True or False: In any counseling or helping situation, the best methods to identify the “real” problem are to establish a trusting relationship with clients and to conduct a thorough assessment.

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2. You prepare a dialysis bag and fill it with 10 mL of water. You place the bag in a 400- mL beaker filled with a solution of 20\% NaCl. (1 point) (a) Which way will chloride ions tend to move: into or out of the bag?

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Every time you view a webpage, your data is captured in small pieces called packets. How are data packets transmitted across the Internet? Multiple Choice through Transmission Control Protocol/Internet Protocol (TCP/IP) through Computer Emergency Response Team (CERT) through International Criminal Police Organization (Interpol)

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Big Stephanos' Pizza of Century City, CA, produces 90,000 Greek pizza pies per year. Annually Big Stephanos' fixed costs are $150,000. The average variable cost per pie is a constant $3.50. The average total cost per pie then is approximately a. $3.50. b. $5.17. c. impossible to determine. d. $3.17.

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$R_1$ $300 \Omega$ $E = 10 \text{ V}$ $I$ $50 \text{ mA}$ $R_2$ $200 \Omega$ $R_L$ $80 \Omega$

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oblem deals with playing cards. The Card API is given below: public class Card { 1- } . suit is "Clubs", "Diamonds", "Hearts", denomination is "2","3","4","5", "6", "7", "8","9", "10", "J", or "Spades" or "A" value is the value of the card number if the card denominat. is between 2 and 10; 11 for J, 12 for Q, 13 for K, 14 for A public Card(String suit, String denomination){} //returns the suit (Clubs, Diamonds, Bearts, or Spades) public String getSuit(){} // returns the denomination (2,3,4,5,6,7,8,9,10,J,Q,K,A) public String getDenomination(){} // returns the String representation of the card ("A of Bearts") public String toString(){} // returns value is the value of the card number if the card denomination is between 2 and 10:11 for J:12 for Q:13 for R:14 for A public int getValue(){} client program includes the following declarations: string[] suits={"Clubs", "Diamonds", "Hearts", "Spades"}; string[] ranks={"2","3","4","5", "6", "7","8","9", "10", "J", "Q", "K", "A"}; ard[] deck = new Card[52]; ou will be writing code that appears in the client program. (20 points) Write a nested loop that will fill deck by calling the Card constructor to crande each of the 52 unique playing cards. Note, after the nested loop has been executed, dets contains 52 unique playing cards.

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4.73 The sphere shown in Fig. 4.82 is constructed of two hemispheres which are perfectly insulated along their contact area. The upper hemisphere, surface 1, has a temperature of 450°K and an emissivity of 0.80, while the lower hemisphere, surface 2, has a temperature of 330°K and an emissivity of 0.60. If the sphere radius is 0.3 m, calculate the net radiant loss from surface 1 using the network method. Figure 4.82 Surface 1 Surface 2

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*13-32. The frame supports the load of $P = 4 \text{ kN}$. As a result, the A992 steel member $BC$ is subjected to a compressive load. Due to the forked ends on this member, consider the supports at $B$ and $C$ to act as pins for $x-x$ axis buckling and as fixed supports for $y-y$ axis buckling. Determine the factor of safety with respect to buckling about each of these axes. 13-33. Determine the greatest load $P$ the frame will support without causing the A992 steel member $BC$ to buckle. Due to the forked ends on the member, consider the supports at $B$ and $C$ to act as pins for $x-x$ axis buckling and as fixed supports for $y-y$ axis buckling.

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Q.3: The spin states of two electron system can be written as $|1,1\rangle = |\uparrow_1,\uparrow_2\rangle$, $|1,0\rangle = (|\uparrow_1,\downarrow_2\rangle + |\downarrow_1,\uparrow_2\rangle)/\sqrt{2}$, $|1,-1\rangle = |\downarrow_1,\downarrow_2\rangle$, $|0,0\rangle = (|\uparrow_1,\downarrow_2\rangle - |\downarrow_1,\uparrow_2\rangle)/\sqrt{2}$. Workout at least 3 different spin states of a three electron system.

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