Find the absolute extrema of the function on the closed interval:
f(x) = x^3 - (3/2)x^2, [-5,2]
minimum (x,y) = (â—»)
maximum (x,y) = (â—»)
[2 Points]
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Find the absolute extrema of the function on the closed interval:
f(x) = x^3 - (3/2)x^2, [-5,2]
minimum
x,y
maximum xy