Texts: Please explain this to me.
2.2. (5 pts) Write the general solution to the differential equation y'' - 5y' + 13y^7 - 21y^6 + 25y^5 - 20y^4 + 12y^3 - 4y^2 = 0 if the roots of its characteristic equation are r = i, 1 + i, 1 + i, 0, 0, 1.
r = 1t i = 1 + i, l - 1 in delta cos(t) + ltsin(t) + w s^2 + 7s + 1 = cos(t) + caesimt + cstecost + ctesmt + b
2.3. (5 pts) Write the FORM of the particular solution Y to the differential equation y'' - 7y' + 16y^5 - 14y^4 + 4y^3 = -2e^(-3t) + 2sin(t) + 2e^(2sin(t-4)) if the homogeneous part of its solution is yh = c + ct + cgt^2 + C4e^(2t) + Cse + Coe^(2cost) + ce^(2sint)
4sin(t) + A5cos(t) + te^2Asin(t) + Acos(t)