The graph of a function $f$ is shown.
Does $f$ satisfy the hypotheses of the Mean Value Theorem on the interval $[0, 5]$?
Yes, because $f$ is continuous on the closed interval $[0, 5]$ and differentiable on the open interval $(0, 5)$.
Yes, because $f$ has a maximum on the closed interval $[0, 5]$.
Yes, because $f$ is continuous on the open interval $(0, 5)$ and differentiable on the closed interval $[0, 5]$.
No, because $f$ does not have a minimum on the closed interval $[0, 5]$.
No, because $f$ is not differentiable on the open interval $(0, 5)$.
No, because $f$ is not continuous on the open interval $(0, 5)$.
If so, find a value $c$ that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.)
$c = $