Given the system of inequalities below, determine the shape of the feasible region and find the corner points of the feasible region. Give the shape as \"triangle\", \"quadrilateral\", or \"unbounded\". Report your corner points starting with the one which has the smallest x-value. If more than one corner point has the same smallest x-value, start with the one that has the smallest y-value. Proceed clockwise from the first corner point. Leave any unnecessary answer spaces blank.
$\begin{cases} x + y \ge 4\\ 6x + y \ge 6\\ x \ge 0\\ y \ge 0 \end{cases}$
The shape of the feasible region is (a) quadrilate
The first corner point is (0 , 4 ).
The second corner point is (10 , 0 ).
The third corner point is (4 , 0 ).
The fourth corner point is (2/5 , 3.6 ).
