1. You need standard aqueous HCl of about 0.04 M concentration. Explain why you need to dilute a whole-number volume rather than use the precise volume required to give 0.04000 M HCl. For example, assuming you had 0.1164 M HCl you would dilute 75.00 mL to 250.0 mL, rather than diluting 85.90 mL to the same volume.
$250.0 \, mL \left( \frac{0.04 \, M}{0.1164 \, M} \right) = 85.9 \, mL \approx 75 \, or \, 100 \, mL.$