Q7 Rich → Poor
4 Points
Two different enzymes, StarBucks and Parking catalyze the same reaction: Rich → Poor. Structural data shows that StarBucks has two different binding sites for Rich. Similarly, Parking also has two different binding sites for Rich. I measure $v_0$ for both enzymes at different [Rich]. My data is shown.
$v_0$
$
Parking
Starbucks
#
[Rich]
Q7.1
2 Points
MOST LIKELY, what is happening at the point marked "$" for StarBucks?
Rich is binding the second, low affinity site, and begins to act as an allosteric inhibitor.
The enzyme is being degraded causing a decrease in reaction velocity.
We start decreasing the total product formed due to saturation.
Some of the substrate is being removed from the reaction.
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Q7.2
2 Points
What is the BEST explanation for the answer to the previous question?
When we remove substrate, product will also decrease in order to maintain equilibrium.
There are two binding sites on Starbucks for Rich, and we see a decrease in velocity only at higher Rich.
Adding more product will cause reaction to slow down when it is already at saturation.
A decrease in enzyme will result in a lower reaction velocity.
