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stephanie mariscal

stephanie m.

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BEST MATCH

Which of the following statements is true of interpersonal conflict? People involved in the conflict believe that there are many ways of resolving their issues. Achieving a satisfactory outcome for each person involved in the conflict is independent of the actions of the other. Either of the two people involved in an interpersonal conflict can be unaware of the disagreement. Both people involved in the conflict believe that they have something to lose if the other person gets his or her way.

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1 Contains the growth plate 2 Covers the outer surface of bone 3 Contains bone marrow 4 Covers all internal surfaces of the bone Match each of the options above to the Items below. Medullary cavity Metaphysis Endosteum Periosteum

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BEST MATCH

The circuit shows a two-op-amp instrumentation amplifier. Derive an expression for $v_o$ in terms of $v_1$ and $v_2$. Assume that $R_1 = 6 \text{ k}\Omega$, $R_2 = 48 \text{ k}\Omega$, $R_3 = 20 \text{ k}\Omega$, gain = 5, and $R_4 = (\text{gain}-1)*R_3 \text{ k}\Omega$. $v_o = (\boxed{\hspace{1cm}})v_1 + (\boxed{\hspace{1cm}})v_2$

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BEST MATCH

Reinforcement Learning 15 points Consider the non-deterministic reinforcement environment drawn below. States are represented by circles, and actions by squares. The Probability of a transitions is indicated on the arc from actions to states. Immediate rewards are indicated above and below states. Once the agent reaches the end state the current episode ends. R=2 0.8 X a X 0.2 0.5 Y 0.5 start 0.8 R=0 0.5 Y b 0.5 X,Y R=5 end 0.2 R=0 1 13. (15 points) Consider two possible policies: always take action X or always take action Y. For each policy, compute the answers to the following questions. (a) What paths could be taken? (b) What is each path's probability? (c) What is each path's reward? (d) What is the utility of each state?

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BEST MATCH

Solve and check the linear equation. 4x + 1 = x + 19 The solution set is {\boxed{\text{}}} . (Simplify your answer.)

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BEST MATCH

Consider a household whose utility is determined by the consumption of two goods, A and B. Let cA and cB denote the consumption of good A and good B, respectively. The utility of this household can be represented by a utility function

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2) (30 pts) The liquid-phase reaction A + B C occurs in an adiabatic CSTR with a volume of 10,000 L. The feed contains 3.0 mol/L of A, 1.5 mol/L of B, and 50 mol/L of solvent, with FBo= 15.0 mol/min. The reaction is second order in A and first order in B, with rate constant follows Arrhenius behavior with pre-factor of 2x107 L2/(mol2-min) and activation energy of 64.0 kJ/mol. The reaction is endothermic with HR of +40 kJ/mol. The heat capacities are 44 J/mol-K for A, 37 J/mol-K for B, and 51 J/mol-K for solvent. HR and the heat capacities are independent of temperature. A) (4 pts) Write the stoichiometric table in terms of fractional conversion of the limiting reactant. B) (20 pts) If the fractional conversion of B is 0.88, find the feed temperature and effluent temperature. C)(3 pts) Would a reactor operated isothermally at the feed temperature have higher, lower, or the same fractional conversion compared to the adiabatic reactor with the same volume? Why? (You do not need to show any calculations.) D) (3 pts) What is the benefit of choosing a solvent with large (rather than small) heat capacity for this system?

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BEST MATCH

Lexie needs to mail her Christmas cards and packages and wants to keep her mailing costs to no more than $500. The number of cards is at least 3 more than three times the number of packages. The cost of mailing a card (with pictures enclosed) is $6 and for a package the cost is $9. Let c represent the number of cards she mails and let $p$ represent the number of packages she mails. Write a system of inequalities to model this situation. Select the correct answer below: $\begin{cases} 6c + 9p \le 500\\ c \ge 3p + 3 \end{cases}$ $\begin{cases} 6p + 9c \le 500\\ p \ge c + 3 \end{cases}$ $\begin{cases} 6c + 9p \le 3\\ c \ge 3p + 500 \end{cases}$ $\begin{cases} 6c + 9p \ge 3\\ c \le 3p + 500 \end{cases}$

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BEST MATCH

The initial-value problem is y''+xy'+4y=0, y(0)=5, y'(0)=-5.

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BEST MATCH

b) y = 2 sin (x + π/3) - 1, for two periods starting at the phase shift (in radians) -π/3

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