Find values for \( b \) such that the triangle has one solution, two solutions (if possible), and no solution.
\[
A=48^{\circ}, a=8
\]
(a) one solution
\[
\begin{array}{l}
b=8, b>\frac{8}{\sin \left(48^{\circ}\right)} \\
8<b<\frac{8}{\sin \left(48^{\circ}\right)} \\
b \leq 8, b=\frac{8}{\sin \left(48^{\circ}\right)} \\
b<\frac{8}{\sin \left(48^{\circ}\right)} \\
b>\frac{8}{\sin \left(48^{\circ}\right)}
\end{array}
\]
(b) two solutions (if possible)
\[
\begin{array}{l}
b=8, b>\frac{8}{\sin \left(48^{\circ}\right)} \\
8<b<\frac{8}{\sin \left(48^{\circ}\right)} \\
b \leq 8, b=\frac{8}{\sin \left(48^{\circ}\right)} \\
b<\frac{8}{\sin \left(48^{\circ}\right)} \\
b>\frac{8}{\sin \left(48^{\circ}\right)}
\end{array}
\]
(c) no solution
\( b=8, b>\frac{8}{\sin \left(48^{\circ}\right)} \)
\( 8<b<\frac{8}{\sin \left(48^{\circ}\right)} \)
\( b \leq 8, b=\frac{8}{\sin \left(48^{\circ}\right)} \)
\( b<\frac{8}{\sin \left(48^{\circ}\right)} \)
\( b>\frac{8}{\sin \left(48^{\circ}\right)} \)
