$NH_3$ v $CH_4$
$CH_4$ is more acidic because its conjugate base is more stable, with a negative charge on the less electronegative C atom.
$NH_3$ is more acidic because its conjugate base is more stable, with a negative charge on the more electronegative N atom.
$CH_4$ is more acidic because its conjugate base is more stable, with a positive charge on the less electronegative C atom.
$NH_3$ is more acidic because its conjugate base is more stable, with a positive charge on the more electronegative N atom.
$H-=-H$ v $H_2C=CH_2$
The alkyne (triple bond) is more acidic because its conjugate base is more stable, with a negative charge associated with an sp hybrid orbital.
The alkyne (triple bond) is more acidic because its conjugate base is less stable, with a negative charge associated with an sp hybrid orbital.
The alkene (double bond) is more acidic because its conjugate base is more stable, with a negative charge associated with an $sp^2$ hybrid orbital.
The alkene (double bond) is more acidic because it's conjugate base is less stable, with a negative charge associated with an $sp^2$ hybrid orbital.