Ace - AI Tutor
Ask Our Educators
Textbooks
My Library
Flashcards
Scribe - AI Notes
Notes & Exams
Download App
timothy maddox

timothy m.

Divider

Questions asked

BEST MATCH

a) c) CH3 O CH3 b) CH3 CH3 d) CH3 O O

View Answer
divider
BEST MATCH

5. In each reaction, i dentify the Lewis acid and the Lewis base. a. $CH_3CH_2OH + (CH_3)_3C^+ \rightleftharpoons CH_3CH_2OH(CH_3)_3$ b. $CH_3CH_2OH + BF_3 \rightleftharpoons CH_3CH_2OHBF_3$ c. $CH_3CH_2Cl + AlCl_3 \rightleftharpoons CH_3CH_2ClAlCl_3$ d. $Br_2 + FeBr_3 \rightleftharpoons Br_2FeBr_3$

View Answer
divider
BEST MATCH

businesses survive. Policies that are will bolster competition and make markets more competitive. Economists will prefer policies that are because they will lead to the best outcomes for society.

View Answer
divider
BEST MATCH

Find the number $a$ such that the line $x = a$ bisects the area under the curve $y = \frac{4}{x^2}$, where $1 \le x \le 4$ Note. The line 'bisects' the region if the area of the portion of the region to the left of the line is equal to the area of the portion of the region to the right of the line.

View Answer
divider
BEST MATCH

Use the superposition method to show that the beam deflection at point C for a 21wL^4 beam is equal to 768EI(0.0273wL^4)/EI. WL and El are constants. Use the discontinuity function method to derive the beam deflection equation for the entire length L and verify the beam deflection at point C as obtained in (1). For x < a, (x-a)^n = 0. For x = a, n = -1, -2. (x-a)^(n+1) dx = -a^(n+1) dx = (x-a)^(n+1). n = 0, n = -1, -2.

View Answer
divider
BEST MATCH

There are 2 alternative projects A and B. Which is more preferrable, if the cost of capital = 10%. Use: 1) replacement chain method; 2)EAA method A: -100; 50; 72 B: -100; 30; 40; 60

View Answer
divider
BEST MATCH

Describe the processes involved, according to the opponent-process theory, in the changes undergone by emotional reactions as a function of experience with the eliciting stimulus. Then apply this theory to explain nicotine addiction.

View Answer
divider
BEST MATCH

Write an error-free Java program to do the following things: 1. Input two integers from the user. (You may input both of the integers at the same time, but your best bet is to input the integers one at a time.) The limit of 2 is to simplify testing; you should write your program so that it can be easily extended to work with more than 2 numbers. 2. If the input integer is not between 1 and 5000000 (non-inclusive), then keep prompting the user to re-enter the number until the integer is within the proper range. 3. Determine if the input number is prime. If N is prime, then print a message stating that it is prime. 4. If the number is not prime, say it is not prime and determine the smallest factor of the number (other than 1). To summarize, you must read in two numbers, make sure they are within the proper range, determine if each number is prime, and, if not prime, determine its smallest factor. There are many ways to do this program, but you must include at least one for loop in your program. Sample output: Input integer 1: 10000000 Input integer 1: 379 Your number 379 is prime. Input integer 2: 5917 The smallest non-unity factor of 5917 is 61 THIS DOES NOT WORK, NEEDS TO BE DONE IN ONE PUBLIC CLASS!!!!! import java.util.*; class IfNotPrimeListFactor { public static boolean isPrime(int num) { for (int i = 2; i <= Math.sqrt(num); i++) { if (num % i == 0) { return false; } } return true; } public static int firstFactor(int num) { for (int i = 2; i <= Math.sqrt(num); i++) { if (num % i == 0) { return i; } } return -1; } public static void main(String[] args) { int SIZE = 2; int value; Scanner sc = new Scanner(System.in); for (int i = 0; i < SIZE; i++) { do { System.out.print("Input integer " + (i + 1) + ": "); value = sc.nextInt(); } while (value < 1 || value > 5000000); if (isPrime(value)) { System.out.println("Your number " + value + " is prime."); } else { System.out.println("The smallest non-unity factor of " + value + " is " + firstFactor(value)); } } } } BAD!!!!^^^^^

View Answer
divider
BEST MATCH

In a study done on the life expectancy of 600 people in a region, the mean age at death was 75 years and the standard deviation was 6.3 years. What is the interval for the mean life expectancy of the middle 97% of the distribution of the sample mean of 60 people?

View Answer
divider
BEST MATCH

Reduce each fraction to lowest terms. Fraction Prime Factorization of the Numerator (a) Prime Factorization of the Denominator (b) a b Fraction in Lowest Terms 1. 6 9 2 \cdot 3 3 \cdot 3 \frac{2 \cdot 3}{3 \cdot 3} \frac{2}{3} 2. 28 36 3. 42 48 4. 35 55 5. 60 96

View Answer
divider