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timothy soto

timothy s.

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2) Ethanol, $C_2H_6O$, is an organic compound commonly used as a solvent and fuel additive. It has a melting point of -114 °C and a boiling point of 78.0 °C. Its enthalpy of vaporization is 38.6 kJ/mol, and its enthalpy of fusion is 4.90 kJ/mol. The specific heats of solid and liquid ethanol are 0.97 J/g·K and 2.3 J/g·K, respectively. How much heat is required to convert 75.0 g of ethanol at -130 °C to the vapor phase at 78.0 °C?

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an aqueous solution of ethyl acetate at room temperature has an initial concentration of 0.15M. calculate the equilibrium concentrations of ethyl acetate ethanol and acetic acid if the equilibrium constant hc at this temperature is 3

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If $f(x) = 3 + \frac{8}{x} + \frac{6}{x^2}$, find $f'(x)$. \newline Find $f'(5)$.

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1. Steam at 5 MPa and 400°C enters a nozzle steadily with a velocity of 80 m/s, and it leaves at 2 MPa and 300°C, with a velocity of 563 m/s. The mass flow rate of the steam is 6.92 kg/s. Determine the heat loss from the nozzle, kJ/s.

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These guanines base-pair with which other nitrogenous base in the double-stranded DNA molecule?

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Current Attempt in Progress Swifty Company provided the following information for the month of October: Beginning cash balance Cash receipts Cash disbursements $35300 460400 485800 Swifty's policy is to keep a minimum end-of-the-month cash balance of $29100. How much will Swifty need to borrow during October?

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Marginal Benefit and Marginal Cost (Dollars) Marginal Cost Q2 Quantity of Shoes Q3 Marginal Benefit Refer to the diagram for athletic shoes. Which of the following would change the optimal quantity to Q1? Multiple Choice Q1 is already the optimal quantity. a decrease in the marginal cost of athletic shoes an increase in the marginal benefit of athletic shoes an increase in the marginal cost of athletic shoes

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You have 1 liter of 12.1% Tris (FW 121.1) and you need 1 liter of 0.01M Tris. Can you make use of the % solution of Tris; if so, how would you proceed?

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Part-11 3 a) Oxygen is compressed from an initial condition of 1 bar and 25°C to a final state of 5 bar and 25°C by an adiabatic compression followed by cooling at constant volume. Calculate the (i) work required (W) [5 marks] (ii) heat transferred (Q) [5 marks] (iii) changes in internal energy (AU) [5 marks] (iv) enthalpy of air (?H) for each process. [5 marks] Air may be considered an ideal gas with the constant heat capacities. $C_V$ = 20.785 J/mol K or (5/2) R $C_P$ = 29.099 J/mol.K or (7/2) R Where R = 8.314 J/mol K 3 b) Sketch the entire process in a single PV diagram for Q3 (a). [5 marks]

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Consider two cases: Case 1: Vertical plate (0.9 m high; 0.5 m wide) at 32°C with air at 22°C. Case 2: Vertical plate (0.5 m high; 0.9 m wide) at 22°C with air at 32°C. Which case gives the higher rate of heat transfer? = 1.983 x 10^5 kg/m sec, p = 1.177 kg/m, cp = 1.0057 kJ/kg°C, k = 0.02624 W/m°C. Given: CONVECTION HEAT TRANSFER Natural (Free) Forced Horizontal Cylinders: 10G PnCinor f O.525GrFre5 Tubes (cylinders): 100(/4000ain Horizontal Cylinders: 20Gr PrCTurbulent flow N0.129(GrPr) R10000 turbulent N023/ m0.4 for heating n0.3 for cooling Vertical Surfaces (cylinder, flat plate): Horizontal Flat Surface 0Gr Pr0 Laminar flow 10rPr10 laminar flow N0.59Gr r 90 20Gr Prc0 Turbulent flow Gr Pn0 turbulent flow 6O= N=0.14GPr Flat Plates Re 00000 turbulent flow 000 N=0.664Re Reynolds Number = ReDVp/ Prandtl Number = PrCP /k Peclet Number = Pe = DVpG/k = (Re.OrGrashof Number = Gr = Dpgt/=Dgt/y

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