As shown below, a 15 kg bar that is 3.2 m long is set up to rotate about its center (the yellow circle). Force B is acting 77 cm from the left end of the bar. Express each answer using appropriate mks units.
A = 20 N
B = 21 N
C = 22 N
$$\theta_A = 77^\circ$$
$$\theta_B = 79^\circ$$
Determine each individual torque, the net torque, and the direction the bar will rotate.
$$\tau_A = 9.89 N(m)$$
$$\tau_B =$$
$$\tau_C = 35.2 N(m)$$
$$\tau_{net} = 24.68 N(m)$$
Direction of rotation = Counterclockwise
