Learning Goal:
To practice Problem-Solving Strategy 15.2 Standing
Waves.
In lab, your instructor generates a standing wave
using a thin string of length $L = 2.25 \text{ m}$ fixed at both
ends. You are told that the standing wave is produced
by the superposition of traveling and reflected waves,
where the incident traveling waves propagate in the
$+x$ direction with an amplitude $A = 3.85 \text{ mm}$ and a
speed $v_x = 12.5 \text{ m/s}$. The first antinode of the
standing wave is a distance of $x = 37.5 \text{ cm}$ from the
left end of the string, while a light bead is placed a
distance of $18.8 \text{ cm}$ to the right of the first antinode.
What is the maximum transverse speed $v_y$ of the
bead? Make sure to use consistent distance units in
your calculations.
Given that the distance from the left end of the string to the first antinode is 37.5 cm, calculate the wavelength of the standing wave
on the string. Remember to convert all measurements into units of meters before performing this calculation.
Express your answer in meters.
$\lambda = 1.50 \text{ m}$
Submit
Previous Answers
? Correct
EXECUTE the solution as follows
Part C
What is the maximum transverse speed $v_y$ of the bead?
Express your answer in meters per second.
? View Available Hint(s)
$v_y = $
Submit
m/s
