The function $f(x) = 5(2x + 8)^2 + 3$ is, in general, not one-to-one and thus does not have an inverse. However, if the domain is restricted to $[-4, \infty)$, then the function is one-to-one and therefore invertible.
Determine $f^{-1}$. Using interval notation, list the domain and range of both $f$ and $f^{-1}$. Recall the aforementioned restriction on the domain of $f$.