Constuct and similar problem to both examples and solve it showing work please!
Example.A
Setting p(=detA -I)=0 yields (1 -(2 -x)=0.-So x=1,2 are the eigenvalues of A To.find the eigenvector of A corresponding to x =1,we need to solve (A-Iv=0. It is easy to see that =[u10]v10 Similarly, the cigenvectors of A corresponding to x =2, are of the form v=[1,],1 0. HOMEWORK 32.Construct a similar problem and solve it de+(A-x=(-x2-x-0
1x=1 (A-IV=
v-[] 2.X=2-