When 84.6 g of alanine ($C_3H_7NO_2$) are dissolved in 550. g of a certain mystery liquid X, the freezing point of the solution is 5.7 $^\circ$C lower than the freezing point of pure X. On the other hand, when 84.6 g of ammonium chloride ($NH_4Cl$) are dissolved in the same mass of X, the freezing point of the solution is 17.8 $^\circ$C lower than the freezing point of pure X.
Calculate the van't Hoff factor for ammonium chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.