Given three noncollinear points, we can find an equation of the form.$$x=a y^{2}+b y+c$$ of the horizontal parabola joining them by solving a system of equations. Work Exercises $59-62$ in order, to find the equation of the horizontal parabola containing the points$$(-5,1), \quad(-14,-2), \quad \text { and } \quad(-10,2)$$.
Does the horizontal parabola open to the left or to the right? Why?