-Obtain the masses, separately, of (2) 50 mL beakers.
-Add between 0.75 and 1.00 g of the copper(II) chloride hydrate salt to each beaker.
-Add enough 6M HCl to dissolve the solid. Each sample will require between 5-10 mL of acid. Do not add more than 10 mL of HCl to each beaker. Be sure to continually swirl the mixture.
-Perform a mass-to-mass conversion and calculate how many grams of magnesium metal are required to react. Your instructor will guide you.
-Multiply step 4 by 1.5. Obtain this new amount of magnesium twice. Do not combine the two batches.
-Slowly add one batch of magnesium to one of the beakers containing your mixture. Repeat with the second mixture.
-If there is any magnesium in the mixture that has not reacted, add an additional 1-2 mL of HCl.
-When the reaction is done, decant (pour off) the liquid into a separate waste beaker.
- Add 5 mL of deionized water to the copper residue, swirl, and decant into the waste beaker.
- Dry the copper metal by placing its beaker on a hot plate.
Data: trial 1 & trial 2
-Mass of 50 mL beaker
-Mass of copper salt
-Stoichiometric mass of Mg
-1.5 x stoichiometric mass of Mg
-Mass of beaker containing dried copper residue