Q3. In the circuit shown below, i(t)= 2*cos(900*t) (A), R₁= 2000 Ω, R2= 500 Ω, RL = 1800 Ω, and L = 0.6 H. Determine the average power dissipated in RL.
4ix
R2
i(t) 1
R
ix
RL
b
3a) In the phasor domain, use the nodal analysis to find the real part of the phasor voltage V (Unit: V):
(V)
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3b) In the phasor domain, use the nodal analysis to find the imaginary part of the phasor voltage V (Unit: V):
(V)
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3c) From a to b, the phasor current I₁ passes through RL. Find the real part of the current I1 (Unit: A):
(A)
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3d) From a to b, the phasor current I₁ passes through RL. Find the imaginary part of the current I₁ (Unit: A):
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(A)
3e) Find the average power, Pavg (Unit: W):
(W)
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