11.2.a. Least square solutions of linear equations 1
0.0/10.0 points (graded)
Find least square solution of the following system of equations:
$$
\begin{cases}
x_1 + 3x_2 = 5 \\
x_1 - x_2 = 1 \\
x_1 + x_2 = 2
\end{cases}
$$
How to enter the solution:
• If the value of a variable is a number, just enter the number.
• If the value of a variable is a formula involving free variables, enter the formula. For example, if you obtain that $x_1 = 1 - 2x_2 + 3x_3$ where $x_2$ and $x_3$ are free, then as the value of $x_1$ you should enter $1 - 2*x\_2 + 3*x\_3$. Use the underscore \_ to indicate subscripts of variables, and $*$ to indicate multiplication.
• If a variable is a free variable, enter the variable name as its value. For example, if $x_2$ is a free variable, then you should enter $x\_2$ as the value of $x_2$.
• If the system has no solutions enter None as the value of one of the variables. In such case you can leave values of the remaining variables blank.
$x_1 = $
$x_2 = $
