A ball is thrown upward, with an initial velocity of 39 meters per second, at an angle of 70° with respect to the horizontal. The ball is thrown from a height of 9 meters off the ground.
The horizontal distance $x$ from the starting point and the height $y$ above the ground of the ball $t$ seconds after it is thrown are given by the parametric equations below.
$x = (v_0 \cos\theta)t$
$y = -4.9t^2 + (v_0 \sin\theta)t + h$
Here $v_0$ is the initial velocity, $\theta$ is the initial angle with respect to the horizontal, and $h$ is the initial height.
Use the equations to answer the following questions.
(a) When does the ball reach its maximum height?
Do not round any intermediate computations. Round your answer to the nearest hundredth.
seconds
(b) What is the maximum height of the ball?
Round your answer to the nearest tenth.
meters
