00:01
Write the given equation y times 6x plus 5 plus 6 dx plus 6x plus 2y dy equal to 0.
00:18
Divide this equation by dx and we get plus 6x plus 2y dy by dx equal to 0.
00:33
Now again divide the equation by this term and we get y times 6x plus 5 plus 6 divide by 6x plus 2y plus dy by dx equal to 0.
00:56
Now dy by dx plus 6x plus 5 plus 6 divide by 6x plus 2y and 2y equal to 0.
01:15
This equation is of the form dy by dx plus p by equal to q.
01:24
So comparing equation 1 with equation 2 we get p is equal to 6x plus y plus 6 divide by 6x plus 2y and q is equal to 0.
01:44
Now the integrating factor is equal to exponential integral of p dx.
01:56
Hence substituting value of p we get exponential integral of 6x plus 5 plus 6 divide by 6x plus 2y dx.
02:13
Now let us solve this integration separately.
02:19
Now we can write this equation as integral of 6 minus y divide by 2 times 3x minus y sorry plus y plus 1 dx.
02:47
This is equal to 6 minus y upon 2 we can take out of bracket and what remains in is 1 upon 3x plus y dx plus integration of 1 dx...