-((d)/(ds)(30(s^(2)+3s+3)))/(s)|_(s)=-2
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The function is $f(s) = \frac{30(s^2+3s+3)}{s}$, and we need to find $-\frac{d}{ds}f(s)$ at $s=-2$. First, let's simplify the function $f(s)$: $f(s) = \frac{30s^2 + 90s + 90}{s} = 30s + 90 + \frac{90}{s} = 30s + 90 + 90s^{-1}$. Show more…
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