If a projectile is fired with an initial velocity of v0...

If a projectile is fired with an initial velocity of v0 meters per second at an angle ? above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations x = (v0 cos(?))t y = (v0 sin(?))t - 1/2gt^2 where g is the acceleration due to gravity (9.8 m/s^2). (Round your answers to the nearest whole number.) (a) If a gun is fired with ? = 30° and v0 = 700 m/s. When will the bullet hit the ground? How far from the gun will it hit the ground? 43301 m What is the maximum height reached by the bullet? 10750 m (b) Find the equation of the parabolic path by eliminating the parameter. y = tan(?)x - g/(2v0^2cos^2(?))x^2

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00:01 Hi, there is a question we say that if a projectile is fired with an initial velocity v0 meters per second at an angle alpha up the horizontal there is a chance is negligible then position is x equal to v0 cos alpha t and y equal to v0 sine alpha t minus half gt squared where g is excretion due to gravity and g has to be taken as 9 .8 meter per second square.

00:38 If a gun is fired with alpha 30 degree v.

00:41 Not 600 meter per second, when will the bullet hit the ground? how far from the gun will it hit the ground? so and what is the maximum height is used by the bullet? they have been given v .0 equal to 600 meter per second and alpha is equal to 30 degrees.

01:10 Alpha is equal to 30 degrees.

01:12 These are the things that are being given and the question says when will the bullet hit the ground now coming back to the question number a bullet hits the ground when y equal to zero so let us plug in zero equal to v0 sine alpha t minus half 9 .8 t squared this is 4 .9.

01:50 That means if you take t as common and the latest plugin b not equal to 600 and sign 30 degree minus 4 .9 t equal to 0.

02:04 1 will be t equal to 0 when it was just fired from the ground but this will not be our answer and this bracket will give us 600 sine 30 degree by 4 .9.

02:20 So 600 into 1 by 2 by 4 .9 this is 300 so time 300 divide by 4 .9 so after 61 .2 2 seconds it will hit the ground how far from the gun will hit the ground how far from the gun so from here i will be dating x equal to v0 kosa into t so v0 is 600 cost 30 degree into 61 .22 into 600 into cost 30 degree this is 31 ,800 13 .13 .17 meters from 17 meters it will hit the ground...

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