Differentiate the function. y = 8e^x + 7 / ?? x y' =
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The function is: $y = 8e^x + \frac{1}{x}$ Now, we differentiate each term separately. The derivative of $8e^x$ with respect to x is $8e^x$. The derivative of $\frac{1}{x}$ with respect to x is $-\frac{1}{x^2}$. So, the derivative of the function Show more…
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