00:01
Hello, here we are with the answers to the given question.
00:02
Let's start the discussion.
00:04
In this context, we are dealing with a case of 100 words.
00:12
In such a scenario, we do have binary address, tag, cache, offset.
00:18
So let's consider the tag of each case, cache of each case, offset of each case.
00:28
Now, the first is 001, next we have 000, cache 006 and 006 again, then we have offset that is 1011, then again here also 1011.
00:51
This is how you go for the entire set of scenario.
00:55
Then we move on to the second question where you deal with the row major.
01:04
The row major element would be considering f5, f0 and lru for two cases.
01:14
So in the first instance, it is 512, here also it is 512...