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Find the two x-intercepts of the function f and show that f'(x) = 0 at some point between the two x-intercepts. f(x) = -2x?x + 9 (x, y) = (-9, 0) (smaller x-value) (x, y) = (-6, 12?3) (larger x-value) Find a value of x such that f'(x) = 0. x = -6 Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that apply.) f(x) = 9x^3, [1, 2] Yes, the Mean Value Theorem can be applied. No, because f is not continuous on the closed interval [a, b]. No, because f is not differentiable in the open interval (a, b). None of the above. If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = (f(b) - f(a)) / (b - a). (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.) c =

          Find the two x-intercepts of the function f and show that f'(x) = 0 at some point between the two x-intercepts.
f(x) = -2x?x + 9
(x, y) = (-9, 0) (smaller x-value)
(x, y) = (-6, 12?3) (larger x-value)
Find a value of x such that f'(x) = 0.
x = -6
Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that apply.)
f(x) = 9x^3, [1, 2]
Yes, the Mean Value Theorem can be applied.
No, because f is not continuous on the closed interval [a, b].
No, because f is not differentiable in the open interval (a, b).
None of the above.
If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = (f(b) - f(a)) / (b - a). (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.)
c =

Find the two x-intercepts of the function f and show that f'(x) = 0 at some point between the two x-intercepts.
f(x) = -2x?x + 9
(x, y) = (-9, 0) (smaller x-value)
(x, y) = (-6, 12?3) (larger x-value)
Find a value of x such that f'(x) = 0.
x = -6
Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that apply.)
f(x) = 9x^3, [1, 2]
Yes, the Mean Value Theorem can be applied.
No, because f is not continuous on the closed interval [a, b].
No, because f is not differentiable in the open interval (a, b).
None of the above.
If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = (f(b) - f(a)) / (b - a). (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.)
c =

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