Y = e^(x-a) + b Find the parameters of the curve, given...

y = e^{(x-a)} + b Find the parameters of the curve, given that the curve is asymptotic to the line y = 2. Choose one: a = -1, b = 2 a = 2, b = 1 a = -0.86, b = 2 a = 0.434, b = 2 a = 1, b = 2

Transcript

00:01 For this particular equation of the form, e -raise to x minus a plus b, and a graph is already given.

00:07 So you can find the parameters as an a and b so that the graph is asymptotic at line y equal to 2.

00:12 So this is the line y equal to 2, which is an asymptote.

00:17 So if y is an asymptote, if y is first off, there is another point through which the curve is passing.

00:24 So let's try to analyze that y equal to 2 can be asymptote when.

00:30 It is getting asymptote when x is approaching negative infinity obviously so we have to find that we have we have we can rewrite mathematically that when limit x is tending towards negative infinity of e raised to x minus a plus b that is equal to the as a vertical uh the horizontal asymptote which is y equal to two so that is nothing but two so when x approaches negative infinity this becomes e raise to minus infinity and e raise to minus infinity is zero so that becomes 0 and b is a constant.

01:02 So that remains as it is.

01:03 It doesn't have to do anything with the limits.

01:06 So that is equal to 2, which means that the value of b is 2.

01:09 That's something which we got already.

01:11 Now if b is 2, so what is the equation which we got? that will be y is equal to e raised to x minus a plus 2.

01:20 Plus 2.

01:21 Now let's look for another point.

01:23 Let's say this is the point which we are taking...

Question

y = e^{(x-a)} + b Find the parameters of the curve, given that the curve is asymptotic to the line y = 2. Choose one: a = -1, b = 2 a = 2, b = 1 a = -0.86, b = 2 a = 0.434, b = 2 a = 1, b = 2

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