00:01
Hello everyone, in this question we are given a pedigree of recessive condition.
00:12
So, here we have to determine the probability of carrier child for third, first and second individual.
00:19
So, for this condition, too small recessive allele will be required in order for the trait to be expressed whereas heterozygous will behave as carrier.
00:35
Now, in the given pedigree we can see that in second generation the first individual is affected which is the child of first one and first two individual.
01:00
So, therefore, they both will be heterozygous in order to produce a homozygous recessive genotype in the child.
01:14
So, they both will be heterozygous, their child will be homozygous now, further since the children of second, first and second two they are not affected.
01:39
So, therefore, the second two individual will be homozygous dominant that is a.
01:49
Now, since this will be homozygous dominant, two and three in the third generation they will be heterozygous and it is clear that the fourth individual in third generation will be homozygous recessive.
02:10
Now, in the first for the first individual we can assume that it can be either homozygous dominant or heterozygous because it is not expressing the recessive trait.
02:23
So, we'll write that third, first can be either heterozygous or homozygous dominant...